Is it possible for Stack Exchange to make available $\LaTeX$ abbreviations for \mathrm{E}, \mathrm{Var}, \mathrm{Cov} (possibly with new commands \E, \Var and \Cov)? The problem is that things like $\mathrm{Var}[X\mid Y]$ look much better than $Var[X\mid Y]$, but we end up losing a lot of time typing that.
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$\newcommand{\E}{\mathrm{E}}$ $\newcommand{\Var}{\mathrm{Var}}$ $\newcommand{\Cov}{\mathrm{Cov}}$ $\newcommand{\Expect}{{\rm I\kern-.3em E}}$
Here is cardinal's solution. At the beginning of your answer type.
$\newcommand{\E}{\mathrm{E}}$
$\newcommand{\Var}{\mathrm{Var}}$
$\newcommand{\Cov}{\mathrm{Cov}}$
After that, just use it. For example:
$$ \Var[X] = \E[\Var[X\mid Y]] + \Var[[\E\mid X]] $$
$$ \Cov[X,Y] = \E[XY] - \E[X]\E[Y] $$
Stask suggested
$\newcommand{\Expect}{{\rm I\kern-.3em E}}$
$$\Expect[X]$$
which looks pretty.
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5$\begingroup$ A somewhat fancier solution is
$\newcommand{\Expect}{{\rm I\kern-.3em E}}$that produces $\Expect[X]$. Unfortunately, you cannot easily extend it to the variance operator. $\endgroup$ – StasK Oct 6 '12 at 2:28 -
11$\begingroup$ @Stas: That's an old hack for
\mathbb E, i.e., $\mathbb E$. This does extend to variance $\mathbb V(X)$ or similar, as you like. The latter doesn't seem too popular though. :-) $\endgroup$ – cardinal Oct 6 '12 at 13:59 -
$\begingroup$ Yay! Thanks, cardinal. I need to learn my $\LaTeX$ better, apparently :) $\endgroup$ – StasK Oct 6 '12 at 15:08
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$\begingroup$ Neat solution. :) But I for one would prefer if these commands were available out-of-the-box. $\endgroup$ – MånsT Oct 8 '12 at 12:12
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8$\begingroup$ (+1 a couple days ago) As a side note, if you want to avoid the empty space at the top of the answer caused by the macro definitions, you can just slip the
\newcommandcalls in at the beginning of the first math-mode block you use in your answer. :-) $\endgroup$ – cardinal Oct 8 '12 at 17:35 -
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$\begingroup$ How do you use this? I have $\Var{\beta}$ but it misses those square brackets. How can you have them? $\endgroup$ – Léo Léopold Hertz 준영 Feb 28 '15 at 21:21
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4$\begingroup$ @Masi:
\newcommand{\Var}[1]{\operatorname{Var}\left[#1\right]}$\endgroup$ – Scortchi - Reinstate Monica♦ Sep 30 '15 at 11:52 -
4$\begingroup$ Beware Although
\newcommandis elegant and convenient, it appears to affect all $\TeX$ markup on the entire page--not just your individual post! This raises the prospect of bad interactions arising from conflicting commands in different posts (and even in comments). I suspect their processing might depend on the sequence in which the posts appear on the page. Thus, both arbitrary and future developments beyond your control could ruin your post! $\endgroup$ – whuber♦ Jul 8 '16 at 18:48
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To typeset an operator, it is much better to use \operatorname instead of \mathrm, as explained on tex.SE: What's the difference between \mathrm and \operatorname?
Compare (first line uses \mathrm, second line uses \operatorname):
$$\mathrm{Var}[x] + 2\mathrm{Var}[y] - \mathrm{E}[x]\mathrm{E}[y]$$
$$\operatorname{Var}[x] + 2\operatorname{Var}[y] - \operatorname{E}[x]\operatorname{E}[y]$$
and notice small white spaces before the operator name in the second line.
As noted by @cardinal, MathJax supports \newcommand. The best way to use it is to put into the formula where the operator first appears, because putting it into a separate formula creates an annoying empty line (see @Zen's answer). So whenever you first need variance, you can type \newcommand{\Var}{\operatorname{Var}}, e.g.
$$\newcommand{\Var}{\operatorname{Var}} \Var[x]+\Var[y]$$
and this will be displayed as
$$\newcommand{\Var}{\operatorname{Var}} \Var[x]+\Var[y]$$
All subsequent formulas can simply use \Var in them, e.g. $\Var[z]$ will become $\Var[z]$.
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For Corr, Cov and Var I usually use \DeclareMathOperator{\Corr}{Corr}, which, done once in an answer, allows me to just write \Corr(X,Y) whenever I need it later, which displays:
$$\DeclareMathOperator{\Corr}{Corr} \Corr(X,Y)$$
Like Amoeba's answer, this ensures spacing is done correctly in a way that \mathrm doesn't. But see newcommand vs. DeclareMathOperator on TEX.SE: Amoeba's answer apparently has the advantage that newcommand gives more flexibility.
But note I can still do \DeclareMathOperator{\E}{\mathbb{E}} \E(X,Y) and produce:
$$\DeclareMathOperator{\E}{\mathbb{E}} \E(X,Y)$$
And of course I can reuse these in a later piece of $\LaTeX$ too: $\E(X)+\Corr(X,Y)$
(In a document DeclareMathOperator can only be used in a preamble but this doesn't seem to cause any difficulty on here.)
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4$\begingroup$ +1. This is perhaps a better way because it's slightly shorter:
\DeclareMathOperator{\Corr}{Corr}vs.\newcommand{\Corr}{\operatorname{Corr}}. $\endgroup$ – amoeba Sep 13 '15 at 21:40
\Varwould make life easier for us. I understand that it would not be universally used, since it is not plain $\LaTeX$. $\endgroup$ – Zen Oct 5 '12 at 18:13\newcommandat the beginning and then use the macro in the rest of the answer. That's often helpful, especially if you need to use it many times. $\endgroup$ – cardinal Oct 5 '12 at 18:46\newcommandin my answers?!?!?!?!? Whoooaaaa! Problem solved. I'll setup a txt with definitions I normally use. Thank you a lot, Prof.! $\endgroup$ – Zen Oct 5 '12 at 19:03\newcommand, since it seems that is the answer to this Q, can you make it official, perhaps w/ a brief tutorial re how it would work? $\endgroup$ – gung - Reinstate Monica Oct 5 '12 at 20:18